Find Forces in Truss Bars BD, CD and CE

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To find the forces in truss bars BD, CD, and CE, calculations indicate that BD has a force of -2.5 kN, CD has 0.866 kN, and CE has 1.73 kN. The analysis assumes that torque stresses on the joints can be ignored, focusing instead on the impact of rolling supports and unsupported joints. It is concluded that the horizontal forces at joint G will allow for movement, relieving any horizontal stresses in bars AC, CE, and EG. Consequently, it is determined that the force in bar CE is zero due to symmetry. This analysis provides a foundational understanding of the forces acting on the truss structure.
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1. Homework Statement

How to find forces in bars BD CD and CE?

Homework Equations


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The Attempt at a Solution



Bd: -2.5 KN
Cd: 0.866 KN
Ce: 1.73 KN

 
Hi Zaza:

Since no one else has posted an answer, I will offer a thought which I hope will be helpful, although I have never previously attempted to analyze this kind of problem.

Since no mention has been made about the nature of the joints between the beams, I assume that torque stresses on the joints can be ignored. You have calculated that the stress on CE is 1.73 KN. I notice that the joint G has a rolling support, and joints C and E are unsupported. I interpret this to mean that any stresses at G due to horizontal forces on AC, CE, and EG will result in G moving left or right, and this motion will relieve any horizontal stresses in AC, CE, and EG. Since any force in CE must be entirely horizontal due to symmetry, the force in bar CE is zero.

Regards,
Buzz
 
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