To find the forces in truss bars BD, CD, and CE, calculations indicate that BD has a force of -2.5 kN, CD has 0.866 kN, and CE has 1.73 kN. The analysis assumes that torque stresses on the joints can be ignored, focusing instead on the impact of rolling supports and unsupported joints. It is concluded that the horizontal forces at joint G will allow for movement, relieving any horizontal stresses in bars AC, CE, and EG. Consequently, it is determined that the force in bar CE is zero due to symmetry. This analysis provides a foundational understanding of the forces acting on the truss structure.