Find how hollow a rock is given its density and its weight in water

AI Thread Summary
A geologist suspects a rock is hollow, as it weighs twice as much in air compared to its weight in water. The density of the solid part of the rock is 2500 kg/m^3, while water has a density of 1000 kg/m^3. Using the relationship between weight, density, and volume, the calculations show that the average density of the rock is 2000 kg/m^3. This leads to the conclusion that 80% of the rock's volume is solid. The solution confirms the rock's hollow nature based on its density and buoyancy in water.
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Homework Statement



A geologist thinks a rock is hollow. The rock weighed in air is twice as much as when it's in water. Find the fraction of the rock's volume that is solid given the solid part of the rock is 2500kg/m^3 and water is 1000kg/m^3


Homework Equations



rho = mass/volume
Fb = rho*volume*gravity
F(normal) = Force gravity (rock in air) - rho(fwater)*V(displaced)*gravity

The Attempt at a Solution


 
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Can you please show your attempt at the solution as per PF guidelines.

Jared
 
Given that density of solid part of rock is 2500kg/m^3, water is 1000kg/m^3, air has neglibile density and the whole object weighs twice is much in air than in water:

Apparent weight = m(object in air)*g - m(fluid displaced)*g
1/2*m(object in air)*g = m(object in air)*g - m(fluid displaced)g
1/2* rho (object)*V*g = rho (object)*V*g - rho (fluid)*V*g
1/2* rho (object) = rho (object) - rho (fluid)
-1/2*rho (object) = - 1000kg/m^3
rho (object) = 2000kg/m^3

therefore
2000kg/m^3 = x*(solid part) + (1-x)*(air)
2000kg/m^3 = 2500kg/m^3*x
x = 2000/2500 = 0.8 or 80%
 
Your answer is correct.
 
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