Find Infinite Product: Solve 1/2n² Puzzle

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Essentially I need to find (if possible) the following infinite product

1 - \frac{1}{2*n^{2}}

So, not quite Wallis number. I must say that I'm at a complete loss, not even sure where to begin.
 
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0.358486649396841... is approximately what the number is (thanks to Matlab).

Looks like anything to you guys?
 
That looks awfully similar to the infinite product for sin z.
 
Hurkyl said:
That looks awfully similar to the infinite product for sin z.

Which is

\sin(\pi\,z)=\pi\,z \prod_{n=1}^\infty\left(1-\frac{z^2}{n^2}\right)

:smile:
 
I'm not familiar, what does it look like?
 
Thanks guys =)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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