(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The acceleration of a particle is given by a_{x}(t)= - 1.94 m/s^{2}+( 3.05 m/s^{3})t.

Find the initial velocity v_{0x} such that the particle will have the same x-coordinate at time t= 4.00 s as it had at t=0.

2. Relevant equations

v_{x}= v_{0x}+ the integral a_{x}dt

3. The attempt at a solution

What I did was set velocity to 0 moved initial velocity over then integrated acceleration to give me this:

-v_{0x}= (-1.94 m/s^{2})t + ((3.05 m/s^{3})t^{2})/2

I then plugged in t=4 and t=0 into the equation which gave me 16.64 -wrong

I feel Im close, I just dont know how else to approach this problem.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Find initial velocity with accelration as a funt. of t

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