- #1
mnafetsc
- 14
- 0
Homework Statement
The acceleration of a particle is given by a_{x}(t)= - 1.94 m/s2 +( 3.05 m/s3 )t.
Find the initial velocity v_{0x} such that the particle will have the same x-coordinate at time t= 4.00 s as it had at t=0.
Homework Equations
vx= v0x + the integral ax dt
The Attempt at a Solution
What I did was set velocity to 0 moved initial velocity over then integrated acceleration to give me this:
-v0x= (-1.94 m/s2)t + ((3.05 m/s3)t2)/2
I then plugged in t=4 and t=0 into the equation which gave me 16.64 -wrong
I feel I am close, I just don't know how else to approach this problem.