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cc2hende
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Homework Statement
A solid cylinder of mass 0.600kg is released from rest and allowed to roll down a board that has an incline of 30degrees to the horizontal floor. If the solid cylinder is released 0.60m above the floor, what is the cylinder's linear speed when it reaches the lowest end of the board? Take into account translational and rotational kinetic energy. Assume no sliding of the cylinder/no friction)
Homework Equations
Rotational KE= (1/2)*I*ω^2
Translational KE= (1/2)*m*v^2
PE1 + KE1 = PE2 + KE2
The Attempt at a Solution
PE1 + KE1 = PE2 + KE2
mgh + 0 = 0 +1/2 mv^2
mgh=1/2mv^2
√2gh=v
√2(9.8m/s2)(0.60m)
=3.43 m/s
I don't know if this is right though because the question throws me off when it says to take translational and rotational KE into account.