1. The problem statement, all variables and given/known data A solid cylinder of mass 0.600kg is released from rest and allowed to roll down a board that has an incline of 30degrees to the horizontal floor. If the solid cylinder is released 0.60m above the floor, what is the cylinder's linear speed when it reaches the lowest end of the board? Take into account translational and rotational kinetic energy. Assume no sliding of the cylinder/no friction) 2. Relevant equations Rotational KE= (1/2)*I*ω^2 Translational KE= (1/2)*m*v^2 PE1 + KE1 = PE2 + KE2 3. The attempt at a solution PE1 + KE1 = PE2 + KE2 mgh + 0 = 0 +1/2 mv^2 mgh=1/2mv^2 √2gh=v √2(9.8m/s2)(0.60m) =3.43 m/s I don't know if this is right though because the question throws me off when it says to take translational and rotational KE into account.