Find Limit of Sequence: 6/7 or Divergent?

iceman_ch
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Homework Statement



Find the limit of sequence if it converges; otherwise indicate divergence.

a_n=(5-9n+6n^4)/(7n^4+5n^3-3)

answers

a=6/7
b=-2
c=5/7
d=diverges

Homework Equations



none

The Attempt at a Solution



The limit of A_n is equal to 6/7 which is one of the answers but, I thought that if the limit dosen't equal zero then it is divergent? Any help would be great.

Thanks
 
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You may be confusing sequences with series. You question involves sequences
 
Well now I feel stupid. I can't believe I missed that. For some reason I thought it was saying series. Thanks for pointing that out.
 
:smile: yeah, the trickiest questions are the one where we don't dare to spot the obvious. I can't count how many times this happens to me with math problems.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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