Find Mass of Object 2 in Two-Mass Pulley System

AI Thread Summary
In a two-mass pulley system, Object 1 (200g) accelerates upwards at 4.90 m/s², prompting the need to find the mass of Object 2. The initial attempts at solving the problem included incorrect equations and sign errors, particularly in the net force calculations. To correctly determine the mass of Object 2, it is essential to set up separate equations for the net forces acting on each mass and ensure accurate representation of all forces involved. A free body diagram for both objects is recommended to visualize the forces, including gravitational and tension forces. The correct approach will lead to the conclusion that the mass of Object 2 is 600 grams.
Fresh Coffee
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Homework Statement


Two masses are attached by a light string and looped over two frictionless pulleys. Object 1 (200g) accelerates upwards at a rate of 4.90 m/s squared. Determine mass of object 2.



Homework Equations

The Attempt at a Solution


I tries doing this but don't think its right.

Fnet= F1 + F2
ma= m1 + m2
-m2g = m1g – ma
m2g=ma-m1g
m2g= m(a-g)
m2g/g=m(a-g)/g
m2=m(a)
m2=(.2kg)(4.90m/s 2)
m2=.98 kg or 980 grams
 
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Fresh Coffee said:

Homework Statement


Two masses are attached by a light string and looped over two frictionless pulleys. Object 1 (200g) accelerates upwards at a rate of 4.90 m/s squared. Determine mass of object 2.



Homework Equations

The Attempt at a Solution


I tries doing this but don't think its right.

Fnet= F1 + F2
ma= m1 + m2
-m2g = m1g – ma
m2g=ma-m1g
m2g= m(a-g)
m2g/g=m(a-g)/g
m2=m(a)
m2=(.2kg)(4.90m/s 2)
m2=.98 kg or 980 grams

Yes, that solution is not correct. The problem has only two masses but your equation "-m2g = m1g – ma" has three different masses in it. you must fix that. Besides, there is also a sign mistake on your net force calculation. Make sure you draw a diagram before attempting to solve any problem like that. Include all the relevant forces in your diagram.

Also (a-g)/g is not equal to a. That's just basic algebra
 
You did not do this correctly.

Start by setting up two different equations by ∑F=ma for each mass.
 
Was anything right?
 
The units look right.
 
Lol ok thanks. I shall endeavour to solve this enigmatic question.
 
Ok so would finding out the net force of object 1 help?
 
It's a start.
 
Ok so I have set up two equations for each mass.

Fnet1=ma

Fnet2=ma

Fnet1=(.2kg)(4.90m/s squared)

Fnet1=.98 N

However I am stumped what to do with Fnet2. I go Fnet2=m(-4.90 m/s squared) then ma=m(-4.90m/s squared) but don't know what to do next.
 
  • #10
Did you do a free body diagram of each mass? Include all the forces acting on each mass. These will add up to Fnet for each case.
 
  • #11
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
 
  • #12
I can't get it. I'v tried all sorts of ways but its that darn net force that I can't get! If I could just get that I'd have it.
 
  • #13
Fresh Coffee said:
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
Are the gravity forces acting on object 1 and 2 the same? If not, then don't call them both Fg. What about Ft? Is that the same for both objects?
 
  • #14
Fresh Coffee said:
Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.
Great, now sum them up to get Fnet.
 
  • #15
mass of object 2 = 600 grams
 
  • #16
Yeah, that's good to know. But sum up all the forces you outlined above in an equation and set it equal to Fnet.
 
  • #17
I don't need to. All I need is mass of object 2.
 
  • #18
that's not correct. You have to sum up all the forces and set it to ma.
 
  • #19
ScreenShot2014-03-27at32025PM_zpsb9fe484f.jpg
 
  • #20
There is a minus sign missing in lines 1 through 3. Everything else seems correct. You should wait until the very last step before plugging in any values such as the m1 and g. Algebra is easier than arithmetic.
 

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