Find Max Power Dissipation in Circuits with Variables

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To find the maximum power dissipation in a circuit with variable resistor R, the relationship between the currents and voltages must be established using Kirchhoff's laws. The power dissipation is expressed as P = i^2 R, and to maximize this, one must differentiate the power equation with respect to R. The discussion suggests using Thevenin and Norton equivalents to simplify the analysis, which may be preferable to direct differentiation. Confusion arises regarding the correct method to find the derivative, with differing results based on sample values for current. Ultimately, applying Thevenin or Norton equivalents can clarify the approach to determine the optimal resistance for maximum power dissipation.
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In the circuit, E, R1 and R2 have constant values. However R has a variable value. FInd an epxression for R that results in the max power dissipation in that resistor.
so do i do this
i_{1} = i + i_{2}
E - i_{1} R_{1} - i_{2} R_{2} = 0
E - i_{1} R_{1} - iR = 0
i_{2} R_{2} - iR = 0
not too sure about the last one...
and the power dissipation in that resitor is given by P = i^2 R But to find the max power dissipation do i plug that expression for i back into the above expression and then differentiate OR sub i into this
\frac{dP}{dR} = 2iR + i^2
i used a sample value for i and got different values for the derivative. Which is correct?
Please help!
 

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You should use your Thevenin equivalent and Norton equivalent for this one - unless they're making you do this using differentiation and limits at least once just to make sure you truly appreciate Thevenin and Norton equivalents.
 
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