Find Max Power from 60Hz 4000A Power Line w/ 200m Wire

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To find the maximum power extractable from a 60Hz, 4000A power line using 200m of wire positioned 20m away, the magnetic field B is calculated using the formula B = (μ₀I)/(2πr). The flux linkage through the rectangular loop formed by the wire is determined, leading to a maximum voltage of approximately 19.909 volts when the length A is optimized at 31.8 meters. The next step involves understanding the relationship between the induced current in the loop and the source current, but the resistance of the second loop remains unknown. Clarification on how the current in one loop induces a current in another is needed to proceed with calculating the power.
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Homework Statement



A 60Hz, 4000A power line passes near your house. You have 200m of wire. The closest you can get to the wire is 20m. Find the maximum power you can extract from the power line. The graphic shows that the loop has to be rectangular with side lengths A and B.

Homework Equations


The Attempt at a Solution



I took the wire to be in the Z direction, and so A is in the r direction. The B field from the wire is.

B = \frac{\mu_0 I}{2 \pi r}

Flux Linkage through the loop:

\psi = \frac{\mu_0 I}{2 \pi} \int_{0}^{B} \int_{20}^{20 + A} 1/r drdz

...

= \frac{\mu_0*4000sin(377t)*b}{2 \pi} * ln(\frac{(20 + A)}{20})

then,

200 = 2a + 2b , b = 100-a

V = \frac {d\psi}{dt} = .3016cos(377t)*(100-A) * ln(\frac{20+A}{20}

I used MatLab to find that the maximum voltage occurs when A = 31.8 meters. The corresponding voltage is 19.909 Volts.

So this is as far as I've gotten. I need either the Z of the load or the current in the loop to find the power, right? Is the induced current related to the source current?
 

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Maybe I can make this easier, I think I just need to know how current on one loop induced a current on another, given that I don't know the resistance of the second loop.

I mean, In this example, I know that the current on the second loop will be 60Hz, but how can I find the magnitude?
 
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