Find Moment of Inertia of Rod w/ Finite Masses | Sleek

AI Thread Summary
The problem involves calculating the moment of inertia of a rod with two point masses attached at its ends, specifically along an axis at one end of the rod. The calculation yields a moment of inertia of 0.005 kg·m², but the provided answer in the textbook is 0.01 kg·m², which is twice the calculated value. The discussion suggests that there may be printing errors in the textbook, as similar discrepancies have been noted in other problems. The accuracy of the rod's length and the setup is confirmed, indicating that the calculation is likely correct. It is recommended to consult a professor for clarification on the textbook's answer.
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Homework Statement


There is a rod of length 0.5m, to the ends of which two finite point masses of 20g each (0.02 kg) each are attached. Find the moment of inertia along the axis passing through one end of the rod, neglecting the moment of inertia of the rod itself.


Homework Equations


I=M*R^2


The Attempt at a Solution



Since the Axis passes through one end, the moment of inertia is,

I = 0.02*(0.5)^2+0.02*(0)^2
= 0.02* 0.25 = 0.005
= 5*10^(-3)

But the answer given is twice the answer I've found (i.e. 10^(-2) ). In many similar questions, the answer is always twice what I get. Am I wrong or the answer printed is wrong?

Thanks,
Sleek.
 
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Are you sure the rod is 0.5m in your question? Your answer seems right to me.
 
Yes, the rod is 0.5m. The question has two sub-questions (the one I pointed above is the second), and the answer from the first one matches what's given in the book. So the datas are correct.

I'm confident that there have been some printing mistakes in the book (there are many, but mistakes in ClassWork problems are always rectified while solving them, HomeWork can be a problem.

Thanks for the reply!

Regards,
Sleek.
 
no prob. talk to your professor about this if you can.
 

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