Find Net Force Neutral Point b/w Q1 & Q2 Charges

AI Thread Summary
To find the net force neutral point between two charges, Q1 and Q2, the equation Fe=kq1q2/r^2 was applied. The calculations resulted in a quadratic equation yielding roots of approximately 0.998459 m and -0.0384593 m. When considering the placement of a third charge (Q3), the order of charges affects the solution, leading to two negative roots when Q1 is placed before Q2. The relevant solution for Q3's position, considering the requirement for a positive distance if it is to the right of Q1, is approximately 0.998459 m. The individual expresses uncertainty about the correctness of their solution but believes it aligns with the problem's requirements.
Sean1218
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Homework Statement



A charge, Q2 = -7.00x10^-6 C, is 8.00 cm to the right of charge Q1 = 6.00x10^-6 C. Where can a third charge be placed, along the line connecting Q1 and Q2, such that it experiences no net force? Give distances relative to Q1 and use a plus sign if the third charge is to the right of Q1

Homework Equations



Fe=kq1q2/r^2

The Attempt at a Solution



I did q1/x^2 = q2/(x+0.08)^2 and solved for x. I got a quadratic which gave me roots 0.998459 and -0.0384593. This is assuming that the order is Q3 then Q1 then Q2.

If I do it with the order as Q1 - Q2 - Q3, then I get two negative roots (the more negative one still matches up with 0.998459 if I take into account the 0.08 between Q1 and Q2).

So, would my answer be -0.998459 m because Q3 is to the left of Q1 and the question said to make it positive is Q3 is to the right? I have one try left to get this right, but I'm not confident this is correct.
 
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Looks right to me.
 

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