Find orthogonal P and diagonal matrix D

phamdat1202
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Homework Statement



A= [1 -1 0]
[-1 2 -1]
[0 -1 1]
find orthogonal matrix P and diagonal matrix D such that P' A P = D

Homework Equations





The Attempt at a Solution


i got eigenvalues are 0, 1, 3 which make D=[0 0 0; 0 1 0; 0 0 3]
how to find P. because in my solution they mentioned about normalised eigenvectors.
 
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Find the eigenvectors. The columns of P are the eigenvectors.
 
i know after i got eigenvalues, i can find eigenvectors which is P.
my question is that in my solution, P are normalised eigenvectors. why they use normalised eigenvector instead of the eigenvector?
 
If you used unnormalized eigenvectors the diagonalization equation is P-1AP=D instead of P*AP=D. The inverse is particularly easy to find with normalized eigenvectors. If P is constructed from normalized, orthogonal eigenvectors then P will be an orthogonal matrix, making P-1=P*.
 
thanks, got it
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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