Find Pluto's year length using Kepler's third law.

AI Thread Summary
To determine Pluto's year length using Kepler's third law, the relationship R^3/T^2 = constant must be applied, where R is the distance from the Sun and T is the orbital period. Given that Pluto is 40 times farther from the Sun than Earth, the equation can be set up as Tp^2 = Te^2 * (40^3). The constant can be derived from Earth's known orbital period, allowing for the calculation of Pluto's year length. Understanding the constant nature of R^3/T^2 for planets orbiting the same star is crucial for solving the problem. The discussion emphasizes the importance of correctly applying Kepler's law to find the solution.
D.J Falcon
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Homework Statement



Pluto is 40 times further from the Sun than we are. How long is a year on Pluto? (Use Kepler's third law.)


Homework Equations



4∏^2/Gm=T^2/r^3


The Attempt at a Solution



Te^2(Earth period)=x*r^3

Tp^2(Pluto period)=x*(40r)^3


I don't know what to do exactly from here. I'm not even entirely sure that I'm going about this the right way.

Any help would be appreciated.
 
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Hint: For every planet [which goes around the sun] in our solar system R^3/T^2=constant.
Why?
 
estro said:
Hint: For every planet [which goes around the sun] in our solar system R^3/T^2=constant.
Why?

I've already made x a constant (T^2/r^3), in the attempt at a solution. I just don't realize what to do from there.
 
I don't know what you mean by:
D.J Falcon said:
I've already made x a constant (T^2/r^3), in the attempt at a solution.
...

First of all you need to understand why for every planet which goes around the same star R^3/T^2 is constant.
Then don't forget what you already know about the difference in R between Earth and Pluto.

I'm already gave you the answer, actually...
 
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