Find Poisson's Ratio of Aluminum from Torsion and Tensile Tests

AI Thread Summary
The torsion test revealed that aluminum has a shear modulus of 4.60x10^6 psi, while the tensile test indicated a modulus of elasticity of 12.2x10^6 psi. To find Poisson's Ratio, the relationship between lateral strain and axial strain is utilized. The formula G = E/(2*(1+v)) connects the shear modulus (G), modulus of elasticity (E), and Poisson's Ratio (v). A hint was provided that this formula could be used to calculate Poisson's Ratio. The discussion concluded with the original poster expressing gratitude for the assistance received.
JPKelly
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1. Torsion test showed aluminum to have shear modulus of 4.60x10^6psi. Under a tensile test, the same specimen showed a modulus of elasticity of 12.2x10^6psi. Find Poisson's Ratio.



2. Poisson's Ratio=lateral strain/axial strain



3. The ratio is a function of both strains. The equations for strain do not have any modulus values in them. I'm not asking for a total explanation, but more of a hint would help.

Thanks,
James
 
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The shear modulus formula will allow you to calculate Poisson's Ratio.

G = E/(2*(1+v))

Where G is the shear modulus, E is the modulus of Elasticity, and v is Poisson's Ratio.

Thanks
Matt
 
Last edited:
Thank you so much! I actually discovered that shortly after I posted the thread.

Thank you again.
James
 
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