Find Position Vector of Point for Half Torque Opposite Direction

  • Thread starter Thread starter bingkei
  • Start date Start date
  • Tags Tags
    Vector
AI Thread Summary
The discussion revolves around finding the position vector of a point where the torque exerted by a force on a particle is half as large and in the opposite direction. The particle's initial position is given as (9.00, 10.00) m, and the force applied is (7.00, 6.00) N. Participants note that multiple points can satisfy the torque condition, but only one can lie on the y-axis. An attempt to solve the problem yielded an incorrect value of 6.57 for the y-coordinate, indicating a misunderstanding of how to isolate the y-axis position. The correct approach requires maintaining the x-coordinate at zero to ensure the point lies on the y-axis.
bingkei
Messages
1
Reaction score
0
A particle is located at the vector position =(9.00 + 10.00) m and a force exerted on it is given by =(7.00 + 6.00) N. Consider another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude.
Multiple such points can exist.
Only one such point can lie on the y-axis
Determine the position vector of such a point
_____ j m




2. Homework Equations :
dot products



3. The Attempt at a Solution :
I've taken the torque (-16) and divided by 2, kept F as (7,6) and kept x of the position vector...I got 6.57 for the y but it was wrong.
 
Physics news on Phys.org
Hi bingkei,

bingkei said:
A particle is located at the vector position =(9.00 + 10.00) m and a force exerted on it is given by =(7.00 + 6.00) N. Consider another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude.
Multiple such points can exist.
Only one such point can lie on the y-axis
Determine the position vector of such a point
_____ j m




2. Homework Equations :
dot products



3. The Attempt at a Solution :
I've taken the torque (-16) and divided by 2, kept F as (7,6) and kept x of the position vector

If you keep the x coordinate from the original position vector, then your new position will not be on the y-axis.

...I got 6.57 for the y but it was wrong.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top