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## Homework Statement

How would we find the potential difference given the frequency of the incident light and the kenetic energy of an the emitted electrons?

## Homework Equations

E= hf-W

V= w/q

e= 1.602*10^-19

## The Attempt at a Solution

Given: f= 7.4*10^15 Hz

KE= 1.9eV

Required: potential difference

Solution: KE= 1.9eV * 1.602*10^ -19 J/eV = 3.0438*10^-19

V= 3.0438*10^-19/ 1.602*10^ -19 = 1.9

The answer is supossedd to be 2.7, I don't think I'm doing this the correct way.