(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Assuming the maximum electric field sustained by dry air in a cloud is 3x10^6 Vm^-1

And a distanceof 1000 meters between earth and cloud. The cloud is 4km long and 1 km wide. ausume uniform eletric field. Find the potential difference.

2. Relevant equations

[itex]V=Ed[/itex]

[itex]\mu = \frac{1}{2}(\epsilon_{0}\times E^2)[/itex]

3. The attempt at a solution

[itex]\mu = \frac{1}{2}(\epsilon_{0}\times E^2)[/itex]

[itex]3\times 10^6 = \frac{1}{2}(8.85\times 10^-12\times E^2)[/itex]

[itex]E=\sqrt{\frac{3\times 10^6}{\frac{1}{2}(8.85\times10^-12\timesE^2)}}[/itex]

[itex]E = 8.23\times10^8[/itex]

using [itex]V=Ed [/itex]

[itex]E = 8.23\times10^8 \times 1000[/itex]

=8.23x10^11 volts

is this right?

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# Homework Help: Find potential energy of cloud

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