Find Projections of b onto a Vector

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The discussion focuses on calculating the scalar and vector projections of vector b onto vector a, with a given as (-1, -2, 2) and b as (3, 3, 4). The initial calculations included a miscalculation in the dot product, which was later corrected. The correct scalar projection is derived from the formula (a dot b)/|a|, leading to a scalar value of 1/3. The vector projection is then computed using the scalar projection multiplied by the unit vector of a, resulting in components that reflect the sign change. The participants confirm the corrections, leading to an accurate solution.
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ii think i did this correct ( i hate projections)

Homework Statement



find the scalar and vector projections of b onto a

Homework Equations



a= (-1, -2 2) b=( 3,3,4)

scalr (a dot b)\|a|
vector (a dot b)\|a| * a/|a|

The Attempt at a Solution




(a dot b)\|a| =(1 =6 +8)/3 =1/3=scalar
1/3* (a/|a|)= 1/3 *(1/3)*a =-1/9, -2/9, 2/9
 
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i made a typo!

i meant to put (-3 -6 +8)/3 =1/3
 
roadrunner said:

Homework Equations



a= (-1, -2 2) b=( 3,3,4)

scalr (a dot b)\|a|
vector (a dot b)\|a| * a/|a|

The Attempt at a Solution




(a dot b)\|a| =(1 =6 +8)/3 =1/3=scalar
1/3* (a/|a|)= 1/3 *(1/3)*a =-1/9, -2/9, 2/9

(He returns after catching his miscopying of a value...) Check your arithmetic here: there is an error in your dot product calculation. Your method looks all right, so the rest should fall into line from there.
 
a dot b

a = (-1, -2 ,2) b=(3,3,4)

-1(3) +(-2)(3) +2(8)= -3 +-6 +8..ooooooh -1 hahaa

is that the erorr you meant
 
roadrunner said:
a dot b

a = (-1, -2 ,2) b=(3,3,4)

-1(3) +(-2)(3) +2(8)= -3 +-6 +8..ooooooh -1 hahaa

is that the erorr you meant

I believe that should do it. Everything else looked right -- basically, your vector projection components will just flip sign. Does that get you the right result?
 
i think so thanks
 
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