- #1

xatu

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**The problem:**

Find the relative numbers of hydrogen atoms in the chromosphere (T=5000 K) in the n=1, 2, 3, and 4 energy levels.

**Solution:**

The Boltzmann distribution of energies is

[itex]n(ε)dε=\frac{2πN}{(πkT)^{3/2}}\sqrt{ε}e^{-ε/kT}dε[/itex]

So using this I calculated the ratio to be, 1 : 5.4 x 10^-11 : 6.7 x 10^-13 : 1.5 x 10^-13.

Can anyone confirm this?