Find Solution of DE: dy/dx+(1/x)y=1/x^2

  • Thread starter Thread starter Eastonc2
  • Start date Start date
Eastonc2
Messages
19
Reaction score
0

Homework Statement


find the general solution of the given DE
dy/dx+(1/x)y=1/x^2


Homework Equations


integrating factor (e^(∫P(x)dx)=e^(lnx)


The Attempt at a Solution


so i put my integrating factor into the equation, and get:

e^(lnx)(dy/dx)+(e^(lnx)/x)y=e^(lnx)/x^2
and can't progress any further. of course, I can integrate the left side of the equation, which leaves me with e^(lnx)y, but the right side is really throwing me for a loop. are there any suggestions out there?
 
Physics news on Phys.org
ok, so it must be getting a little too late for my brain. e^lnx is...x
so this was a major waste of time/space
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top