Find speed using distance and acceleration?

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SUMMARY

The discussion focuses on calculating the speed of a man entering water after jumping from a height of 4.7 meters, with a downward acceleration of 9.8 m/s² due to gravity. The key equations to use are (distance) = (initial velocity) * t + (1/2) * (acceleration) * t² to determine time, and (final velocity) - (initial velocity) = (acceleration) * t to find the final speed. The initial velocity is zero, and the acceleration is negative, which must be accounted for in calculations. This approach provides a clear method for solving the problem step-by-step.

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Hi everyone,
hopefully someone hear can help me.

a man jumps into a swimming pool from a height of 4.7m assuming that his downward acceleration is 9.8 m s2 due to gravity, at what speed does he enter the water.

I really need help knowing what equations to use, i realize i need to work out the time taken and use that to calculate the overall speed but i am having trouble displaying that as i need to show all my workings.

Thanks for your time.
 
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You could use the formula (distance)=(initial velocity)*t + (1/2)*(acceleration)*t^2 to find the time, using initial velocity = 0, acceleration = -9.8 and distance = 4.7.

Then you could use the formula (final velocity)-(initial velocity) = (acceleration)*t, using the same acceleration and time. Dont forget the negative sign in both accelerations.

Hope this helped.
 
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