Find Spring Position After Attaching 2.7kg Mass

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To find the new position of the spring after attaching a 2.7 kg mass, the spring constant is given as k = 47 N/m. The initial position of the spring is at 15 cm on the ruler. The extension caused by the mass needs to be calculated using the formula for spring force and gravitational force. The incorrect assumption was made that the final position is 141 cm, which does not align with the correct calculations. Proper calculations should yield the accurate extension and final position of the spring on the ruler.
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A spring with k = 47 N/m hangs vertically next to a ruler. The end of the spring is next to the 15 cm mark on the ruler. If a 2.7 kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks?

I got the answer to be 141 cm because I thought that the 15cm is to be converted into meters, can anyone help me with this question?
 
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yes the cm should be converted to metres

what is the extension as a result of the mass being attached?
 
I got 141 cm but that's not correct. I can't figure out the correct answer.
 
bosox3790 said:
I got 141 cm but that's not correct. I can't figure out the correct answer.

how did u get that?
 
I used 0+mg(0.15m + change in y)=0+ .5k(change in y)^2
 

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