Find the appropriate delta for f(x)=1/x - 0.5

  • Thread starter Thread starter xviddivxoggmp3
  • Start date Start date
  • Tags Tags
    Delta Epsilon
xviddivxoggmp3
Messages
2
Reaction score
0

Homework Statement



find a number delta

Homework Equations



f(x) = 1/x

| 1/x - 0.5 |<0.2 whenever | x - 2 | < delta

The Attempt at a Solution



how would you factor out a negative exponent?
is this possible?
i think i can get x out from under the 1/x with using negative exponents, but how would i factor it out? is this the wrong way to go with this?

|1/x - 1/2| < 0.2
| x - 2|^-1 < 0.2
 
Physics news on Phys.org
your equation is wrong as you suspected...

|1/x-1/2|\neq |x-2|^{-1}

I suggest this first approach:

|1/x-1/2|=|(2-x)/2x|=|1/2x||x-2|

So that now finding delta such that |x-2|<delta ==> |1/x-1/2|<0.2 is equivalent to finding delta such that |x-2|<delta ==> |x-2|<|2x|0.2=0.4|x|

This reads "As soon as the distance from x to 2 is smaller than 0.4 times the distance from x to 0, then we have |1/x-1/2|<0.2".

Pick your favorite delta satisfying this.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top