Find the area below the graph of f, but f is in fractional form?

LilTaru
Messages
80
Reaction score
0

Homework Statement



Find the area below the graph of f.

f(x) = (2x + 5)/[(x + 2)2(x + 3)2] xE [0, 1]

Homework Equations



I know the area under the graph is the definite integral with upper limit = 1; lower limit = 0.

The Attempt at a Solution



I have such a hard time evaluating integrals when they are in fractional form. I know if G(x) is the antiderivative of f, then:

Area = G(1) - G(0)

But, I don't know how to find an antiderivative for f? It seems impossible to me! Someone please help!
 
Physics news on Phys.org
Have you tried partial fractions? They're going to be very useful here.
 
We never learned how to use them... Is there a website that shows how to use them?
 
Nevermind... Found a website with a similar question and a step-by-step guide of how to solve it and why! It was really helpful! Thanks for putting me on the right track!
 
It was no problem. Have a great day!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top