i made a pretty picture but i cant get it to upload(adsbygoogle = window.adsbygoogle || []).push({});

oh well...i'll try to explain it

a circle of radius 3cm is inside a circle of radius 8cm (in the middle). On top of these two circles is a wedge (i think...it's like a triangle except curved at the end to fit the edge of the larger circle) which has an angle of 45 degrees at the centre of the cirlces.

what is the area of the larger circle without the wedge or the smaller cirlce?

I got an answer...but i'd like to see if it's right or not, and also if there's a simpler way of doing it.

This is what I did:

area of the bigger cirlce = 64pi

area of the smaller circle = 9pi

area of the larger wedge = integral of x - (64 - x^2)^1/2 between 0 and 8

i havent actually learned how to do that algebraicly, but there's this nifty little function on my calculator...

i get 50.27cm squared

(can someone show me how to integrate that function anyway just for the hell of it?)

area of the smaller wedge = integral of x - (64 - x^2)^1/2 between 0 and 3

= 23.42cm squared

(64pi - 9pi) - (50.27 - 23.42) = 145.95cm squared

so...

Q1. Did I do it right?

Q2. If not, how do i do it?

Q3. If so, is there an easier way i could have done it?

Q4. How do you integrate non-linear functions raised to a power?

ta in advance

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# Find the area

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