Find the Cartesian equation for .

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Homework Statement


r = 4sec(θ)

Homework Equations


x2 + y2 = r2
y = rsin(θ)
x = rcos(θ)

The Attempt at a Solution


Given that r = 4sec(θ), I replaced sec(θ) with 1/cos(θ) and got x = 4. The problem is that I'm not sure if that's the final answer because I have been unable to find r, y or θ.
 
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Is that the whole problem statement? We can't help if we don't see the complete statement.

Did they expect you plot it or convert it to xy coordinates?

If it's a conversion to xy then whatif you place the secant on the other with the r?
 
Calpalned said:

Homework Statement


r = 4sec(θ)

Homework Equations


x2 + y2 = r2
y = rsin(θ)
x = rcos(θ)

The Attempt at a Solution


Given that r = 4sec(θ), I replaced sec(θ) with 1/cos(θ) and got x = 4. The problem is that I'm not sure if that's the final answer because I have been unable to find r, y or θ.

The cartesian form of r = 4sec(θ) IS x=4. It's a vertical line y can be anything. Why do you think you should be able to find r, y or θ?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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