Find the derivative of the function(Quotient rule)

  • Thread starter GustX
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In summary: Ah I see, I changed it up and it seems closer to the answer, but how do you transform from(-27x^8+12x^11 - 3x^14)/ ((x^9)^2)to( what do we do to the denominator)-27/x^10 + 12/ x^7 - 3/ x^4which is the answer##(x^9)^2 = x^{18}## and ##\frac{1}{x^{18}}=x^{-18}##. So for example the first term is ## -27x^8 \cdot x^{-18}= -27x^{-10
  • #1
GustX
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Homework Statement


Find the derivative of the function

[itex]
y = (3-2x^3+x^6 )/x^9
[/itex]

Homework Equations


Derivatives

The Attempt at a Solution


I have tried to use the quotient rule

and got to
[itex]
-6x^11 + 6x^14 - 27x^8 + 18x ^24 - 9x ^14 / (x^9)^2
[/itex]
Which doesn't look close to the answer
[itex]
-27/x^10 + 12/x^7 - 3 / x^4
[/itex]
 
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  • #2
Can you type in the steps to see what you have done so far? And you can as well use the product rule, it's the same.
I assume you have calculated ##(-9)(-2x^3)x^{8} = 18x^{24}## which is wrong. It has to be ##18x^{11}##.
 
Last edited:
  • #3
fresh_42 said:
Can you type in the steps to see what you have done so far? And you can as well use the product rule, it's the same.
1st Part

(-6x^2+6x^5)(x^9) - ( 3-2x^3 + x^6) (9x^8)

2nd Part

-6x^11 + 6x^14 - (27x^8 - 18x^24 + 9x^14)

3rd Part

-6x^11+6x^14 - 27x^8 + 18x^24-9x^14

lol its hard to type math with itex
finished posting.
 
  • #4
GustX said:
1st Part

(-6x^2+6x^5)(x^9) - ( 3-2x^3 + x^6) (9x^8)

2nd Part

-6x^11 + 6x^14 - (27x^8 - 18x^24 + 9x^14)

3rd Part

-6x^11+6x^14 - 27x^8 + 18x^24-9x^14

lol its hard to type math with itex
finished posting.
See my editorial above: ##x^3 \cdot x^8 = x^{11}## not ##x^{24}##.
 
  • #5
fresh_42 said:
See my editorial above: ##x^3 \cdot x^8 = x^{11}## not ##x^{24}##.
Ah I see, I changed it up and it seems closer to the answer, but how do you transform from

(-27x^8+12x^11 - 3x^14)/ ((x^9)^2)

to( what do we do to the denominator)

-27/x^10 + 12/ x^7 - 3/ x^4

which is the answer
 
  • #6
##(x^9)^2 = x^{18}## and ##\frac{1}{x^{18}}=x^{-18}##. So for example the first term is ## -27x^8 \cdot x^{-18}= -27x^{-10}=\frac{-27}{x^{10}}##.
 
  • #7
fresh_42 said:
##(x^9)^2 = x^{18}## and ##\frac{1}{x^{18}}=x^{-18}##. So for example the first term is ## -27x^8 \cdot x^{-18}= -27x^{-10}=\frac{-27}{x^{10}}##.
lol I never woulda thought it that far
 

Related to Find the derivative of the function(Quotient rule)

1. What is the quotient rule for finding the derivative of a function?

The quotient rule is a formula used to find the derivative of a function that is expressed as a quotient of two other functions. It states that the derivative of the quotient is equal to the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator.

2. When do we use the quotient rule to find the derivative of a function?

The quotient rule is used when the function can be written as a fraction of two other functions, and neither of the functions can be simplified or factored. In other words, when the function is in the form of f(x)/g(x), where f(x) and g(x) are both functions of x.

3. How do we apply the quotient rule to find the derivative of a function?

To apply the quotient rule, we first identify the numerator and denominator of the function. Then, we take the derivative of the numerator and denominator separately. Next, we plug these values into the quotient rule formula and simplify the expression to find the derivative of the original function.

4. Can the quotient rule be used for any type of function?

No, the quotient rule can only be used for functions that can be expressed as a fraction of two other functions. It cannot be used for functions that involve addition, subtraction, multiplication, or division of multiple functions.

5. Are there any alternative methods for finding the derivative of a function?

Yes, there are other methods for finding the derivative of a function, such as the product rule, chain rule, and power rule. The method used depends on the form of the function and personal preference. It is important to be familiar with all methods in order to find the most efficient way to find the derivative for a given function.

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