Find the electric field at a point away from the charged cylinder's axis

AI Thread Summary
The electric field at a point outside a charged conducting cylinder is zero due to the absence of enclosed charge within the cylinder. The point of interest is located 10 cm from the cylinder's axis, well beyond the conducting shell. Since the charge on the conducting shell is negative, it does not affect the electric field outside the shell. The conclusion is confirmed that the electric field in this scenario is indeed zero. The analysis correctly identifies the conditions leading to this result.
Fatima Hasan
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Homework Statement


screenshot_56.png


Homework Equations



##E=\frac{kQ}{r^2}##

3. The Attempt at a Solution
##Q_{enclosed} = 0 ## , because there is no charge inside the conducting cylinder.
E = 0
Can anyone check my answer please ?
 

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Fatima Hasan said:
because there is no charge inside the conducting cylinder.
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
 
Doc Al said:
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
 

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    rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
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Note that the charge on the conducting shell is negative.
 
Doc Al said:
Note that the charge on the conducting shell is negative.
7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
 

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  • 7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
    7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
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Now you've got it.
 
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