Find the equation of hyperbola

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The discussion revolves around finding the equation of a hyperbola and the circle formed by concyclic points where tangents from the point (2√2, 1) intersect the coordinate axes. The equation of the tangent is given as y = mx + √(a²m² - b²), with m defined as tan^{-1}(1/√2). The condition for tangency is c² = a²m² - b², but there are two unknowns, a and b. Participants suggest using the concyclic nature of the points or finding the equation of the second tangent to derive relationships between the intercepts. The conversation highlights the need for additional data to solve for the hyperbola and circle equations effectively.
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Homework Statement


From the point (2√2,1) a pair of tangents are drawn to \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2} = 1, which intersect the coordinate axes in concyclic points . If one of the tangents is inclined at an angle of tan^{-1}\frac{1}{√2} with the transverse axis of the hyperbola , then find the equation of
i) hyperbola ii)circle formed using concyclic points

Homework Equations



The Attempt at a Solution


Equation of tangent
y=mx+\sqrt{a^2m^2-b^2}
where m = tan^{-1}\frac{1}{√2}
Passing it through the given point will give me an equation in a and b. But there are two unknowns.
 
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Condition for tangency is ##c^2=a^2m^2-b^2##. Can you find c?

edit: sorry didn't see that you already did this. I think you have to use the fact that the points are concyclic, or find the equation of the other tangent.
 
Last edited:
MrWarlock616 said:
Condition for tangency is ##c^2=a^2m^2-b^2##. Can you find c?

edit: sorry didn't see that you already did this. I think you have to use the fact that the points are concyclic, or find the equation of the other tangent.

But how?
 
utkarshakash said:
But how?

I think some data might be missing. All I can think of is that the slope of the tangent is -B/A where A and B represent the intercepts of this tangent. A relation between A and B can be found by looking at the circle formed by the points of the intercept, as they are at equal distances from the centre...but the centre is not known too..
 
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