Find the equivalent resistance seen by the source

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Discussion Overview

The discussion revolves around finding the equivalent resistance seen by a source in a given circuit, as well as calculating additional values related to current and voltage. Participants are attempting to solve a homework problem involving circuit analysis using Kirchhoff's laws and Ohm's laws.

Discussion Character

  • Homework-related
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant initially calculated the equivalent resistance as 6Ω but believed the correct answer should be 8Ω, leading to confusion.
  • Another participant confirmed they also calculated the equivalent resistance as 8Ω but later corrected themselves to 6Ω.
  • Several participants consistently reported their equivalent resistance as 6Ω, suggesting a potential error in the 8Ω calculation.
  • One participant humorously noted the possibility of a "buggy calculator" affecting their calculations.
  • A participant suggested that after determining the equivalent resistance, further calculations for voltage and current through the circuit could be performed using the formula V = I * R.

Areas of Agreement / Disagreement

There is disagreement regarding the correct value of the equivalent resistance, with some participants asserting it is 6Ω while others initially believed it to be 8Ω. The discussion remains unresolved as to which value is correct.

Contextual Notes

Participants express uncertainty about their calculations and the reasoning behind the differing answers. There is no consensus on the correct equivalent resistance, and the discussion highlights the complexity of circuit analysis.

scanferr
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Homework Statement



Find:

a) the equivalent resistor seen by the source;
b) value of i0;
c) value of v;
d) value of v0.

http://img823.imageshack.us/img823/4406/dasso.jpg


Homework Equations



Kirchoff's laws and Ohm's laws

The Attempt at a Solution



To solve b,c,d I need to get a right which I didn't. I got 6Ω for the equivalent resistor and the right answer is 8Ω. I don't understand why!
Isn't the circuit made of those 36Ω and 44Ω in series and the 40Ω,10Ω,30Ω in series and the parallel of those with the rest? I don't get why I got it wrong.

Can you people help me?
 
Last edited by a moderator:
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scanferr said:

Homework Statement



Find:

a) the equivalent resistor seen by the source;
b) value of i0;
c) value of v;
d) value of v0.

http://img823.imageshack.us/img823/4406/dasso.jpg

Homework Equations



Kirchoff's laws and Ohm's laws

The Attempt at a Solution



To solve b,c,d I need to get a right which I didn't. I got 6Ω for the equivalent resistor and the right answer is 8Ω. I don't understand why!
Isn't the circuit made of those 36Ω and 44Ω in series and the 40Ω,10Ω,30Ω in series and the parallel of those with the rest? I don't get why I got it wrong.

Can you people help me?
Hello scanferr. Welcome to PF !

[STRIKE]I also get 8Ω for the equivalent resistance.[/STRIKE]

Show how you got your answer.

Added in Edit:

Actually, I also get 6Ω .

I don't know why I initially wrote 8Ω .
 
Last edited by a moderator:
I got 6 ohm as my answer !
 
6 ohms here, too. How can we all be using the same buggy calculator? :wink:
 
I get 6 ohms too. 8 ohms is just wrong. It happens.

Anyway, you would then calculate the voltage between the top and bottom supply rails and calculate the currents through the parallel resistors and networks.

V = I * R. I = 8 amps. R = 6 ohms.
 
Thanks guys!

It seems the solution is wrong then. It happens yes, and I was kinda confused because I didn't know how 8ohms could be right!
 

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