Find the Error: Solving Homework Problems

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Harmony said:
May I know which part of my solution went wrong? In the end the answer gives x/2 instead of 0.

Since y' (x) contains only odd powers of x, the n=1 term does not vanish when you take the derivative of the series. Therefore,

y'' (x)= \sum_{n=1}^{\infty} \frac{(-1)^n (2n)(2n-1) x^{2n-2}}{4^n (n!)^2}

The extra x/2 in your answer will be canceled by the n=1 term.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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