shamieh
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A little bit confused.
Find the exact length of the curve
$$y = \frac{1}{4}x^2 - \frac{1}{2}\ln x$$
$$1 \le x \le 2$$
Using the formula: $$y = \sqrt{1 + (\frac{dy}{dx})^2} \, dx$$
I obtained this:
$$\int ^2_1 \sqrt{ \frac{1}{2} + \frac{x^2}{4} + \frac{1}{4x^2}}$$
Now my problem is I'm stuck. If I bring the $$\frac{1}{2}$$ out I will have a $$\sqrt{\frac{1}{2}}$$ which won't really do me any good. Any suggestions?
Find the exact length of the curve
$$y = \frac{1}{4}x^2 - \frac{1}{2}\ln x$$
$$1 \le x \le 2$$
Using the formula: $$y = \sqrt{1 + (\frac{dy}{dx})^2} \, dx$$
I obtained this:
$$\int ^2_1 \sqrt{ \frac{1}{2} + \frac{x^2}{4} + \frac{1}{4x^2}}$$
Now my problem is I'm stuck. If I bring the $$\frac{1}{2}$$ out I will have a $$\sqrt{\frac{1}{2}}$$ which won't really do me any good. Any suggestions?