Find the final temperature of the sample.

AI Thread Summary
To find the final temperature of the oxygen gas after expansion, the initial conditions include a volume of 1000 cm³ at 45.0°C and a pressure of 1.01 * 10^5 Pa, expanding to a volume of 1450 cm³ and a pressure of 1.06 * 10^5 Pa. The calculation for the final temperature was initially performed using the formula t2 = (p2v1/p1v1) * t1, resulting in a value of 484.2 K. However, the error was identified as needing to convert this temperature to degrees Celsius instead of Kelvin. The discussion also includes a request for assistance with another related question.
noname1
Messages
131
Reaction score
0
Oxygen gas having a volume of 1000 cm3 at 45.0°C and 1.01 *10^5 Pa expands until its volume is 1450 cm3 and its pressure is 1.06 * 10^5 Pa.

a) Find the final temperature of the sample.

t2 = (p2v1/p1v1) * t1t2 = [(1.06*10^5 * 1450 *10^-6) / (1.01*10^5 * 1000 *10^-6)] * 318.2 = 484.2I input the answer but it is wrong can't find out what i am doing wrong
 
Last edited:
Physics news on Phys.org
Can you provide the full statement of the problem? What is the question that is being asked? If it is the final temperature of the gas, should the answer be in Kelvin or in degrees Celsius?
 
sorry forgot that portion updated the original post and noticed that i have the problem done correctly, the only problem was that the answer needed to be in degrees instead of kelvin...

I have another question here if you had the time to look at it i would appreciate it

https://www.physicsforums.com/showthread.php?t=399321
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top