A cube, placed in a region of electric field, is oriented such that one of its corners is at the origin and its edges are parallel to the x, y, and z axes as shown to the left. The length of each of its edges is 1.1 m.
(a) What is the flux through the cube if the electric field is given by E = 3.00y?
3*1.1^3 = 3.993
flux = 3.993Nm^2/C
(b) What is the flux through the cube if the electric field is given by E = -4i + (6 +3y)j
flux = ?
flux = E dot A = |E||A|cos(theta)
The Attempt at a Solution
-4(1.1)^3 + (6+3*1.1)*1.1^2 = 5.929Nm^2/C
which isnt correct. I though that you have to find the flux in the x and y directions then just sum them up to get the total flux. Do I need to find the angle between the magnitude of the vectors?