Find the height from which the ball was thrown

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AI Thread Summary
A ball is thrown from a building at an initial velocity of 8.0 m/s at a 20-degree angle below the horizontal, hitting the ground after 3.00 seconds. To calculate the horizontal distance, the correct formula involves the initial horizontal velocity and the time of flight. The height from which the ball was thrown can be determined using kinematic equations, specifically focusing on the initial height rather than the maximum height reached. It is emphasized to avoid using formulas that assume an initial height of zero, as they do not apply in this scenario. Basic kinematics should be utilized for accurate calculations.
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Homework Statement


A ball is tossed from an upper story window of a building. The ball is given an initial velocity of 8.0m/s at an angle of 20.0 below the horizontal. It strikes the ground 3.00s later.

a) How far horizontally from the base of the building does the ball strike the ground?
b) Find the height from which the ball was thrown
c)How long does it take the ball to reach a point 10.0 below the landing?


Homework Equations


for a. the equation is R=vxit=vicostheta)*2t
for b. h=v^2sin^2thetai/2*g
for c. I think its Rmax


The Attempt at a Solution


ive plugged in the values to the equations but i still don't get the correct answer
 
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Part a) should be straightforward. What is the initial horizontal velocity? Does the horizontal velocity change at all?

you're also given the time... so you can calculate the horizontal displacement.
 
innightmare;1432888 [h2 said:
Homework Equations[/h2]
for a. the equation is R=vxit=vicostheta)*2t

Why 2t?

for b. h=v^2sin^2thetai/2*g

They're not asking for the height the object reaches (which you won't get from this equation anyway... this equation only works when the initial height is 0)... they're asking for the height from which it is thrown.

Don't try to use those formulas... stick to the basic kinematics formulas. Keep it simple.
 
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