- #1

- 10

- 0

## Homework Statement

[tex]\int\frac{sin^{2010}x}{2010}[/tex]

## The Attempt at a Solution

All that I could do was to :

[tex]\frac{1}{2010^{2}}[/tex][tex]\int tan x [/tex]dt

Please help me futher!

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- Thread starter xphloem
- Start date

- #1

- 10

- 0

[tex]\int\frac{sin^{2010}x}{2010}[/tex]

All that I could do was to :

[tex]\frac{1}{2010^{2}}[/tex][tex]\int tan x [/tex]dt

Please help me futher!

- #2

- 10

- 0

t=[tex]sin^{-1}[/tex][tex]t^{\frac{1}{2010}}[/tex]

- #3

Defennder

Homework Helper

- 2,591

- 5

Are you sure this isn't supposed to be a definite integral? Because otherwise the indefinite integral would take about forever to evaluate.

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