Find the inverse laplace transform of this function

mingming
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Homework Statement


F(s) = 3/(s(s^2 +2s + 5))


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The Attempt at a Solution


I have used partial fraction using coefficients.

F(s) = (3/5)s - (3/5) ((s+2)/(s^2 +2s + 5))
and reduce s^2 +2s +5 by completing the square
F(s) = (3/5)s - (3/5) ((s+2)/((s+1)^2 + 4))
I am having trouble finding the right inverse laplace for the second term since (s+2) must be equal to (s+1) to apply the inverse laplace formula in the table...what should i do ...
 
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Use the fact that s+2 = (s+1)+1 and break that term into two terms.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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