Find the inverse Laplace transform?

Success
Messages
75
Reaction score
0

Homework Statement


Find the inverse Laplace transform of e^(-3pi*s)/(s^2+2s+3).


Homework Equations


I know that you're supposed to factor out the e^(-3pi*s) and the other part becomes 1/(s+1)^2+2 but how do you get the answer? I'm confused.


The Attempt at a Solution


The answer is y=(1/sqrt(2))u3pie^(-(t-3pi))*sin(sqrt(2))(t-3pi)
 
Physics news on Phys.org
Success said:

Homework Statement


Find the inverse Laplace transform of e^(-3pi*s)/(s^2+2s+3).


Homework Equations


I know that you're supposed to factor out the e^(-3pi*s) and the other part becomes 1/(s+1)^2+2 but how do you get the answer? I'm confused.


The Attempt at a Solution


The answer is y=(1/sqrt(2))u3pie^(-(t-3pi))*sin(sqrt(2))(t-3pi)

Show your work. According to PF Rules you are not supposed to just ask us to do the problem for you.
 
  • Like
Likes 1 person
I already did some work in #2 template. I really don't know what to do next.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top