Find the Least Upper Bound for P(X>=5) with Chebychev Probability and E[e^X]=19

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To find the least upper bound for the probability P(X>=5) given E[e^X]=19, Chebyshev's inequality is applied. The discussion suggests using the transformation e^X=Y, leading to the inequality P(e^X>=5) <= E(Y)/5. However, the derived upper bound of 19/5 is deemed incorrect by the quiz, prompting a reevaluation of the relationship between X and e^X. The key question remains how to accurately bound e^X when X is at least 5. Further insights are needed to resolve the discrepancy in the calculated probability.
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A non-negative random value X such that

E[e^X]=19
If p be the probability that the random value is at least 5 then what is the least upper bound you can give for the probability p with this information?

i think that i must use the type of chebychev like this

p(X>=5)<=(E(X)/5) but we have E(e^X) if i put e^X=Y then i will have this

p(e^X>=5)<=(E(Y)/5) and i am taking ln(log) and i have: p(X>=5)<=19/5 but the quiz says that 19/5 its not correct any ideas?
 
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