- #1
MHD93
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Hi
Find the limit:
[tex] \lim_{x\to0}\frac{\sin x-x }{x^3} [/tex]
Find the limit:
[tex] \lim_{x\to0}\frac{\sin x-x }{x^3} [/tex]
What have you tried?Mohammad_93 said:Hi
Find the limit:
[tex] \lim_{x\to0}\frac{\sin x-x }{x^3} [/tex]
The limit of the function $\frac{\sin x-x}{x^3}$ as $x$ approaches $0$ is $-\frac{1}{6}$. This means that as $x$ gets closer and closer to $0$, the value of the function approaches $-\frac{1}{6}$.
To calculate the limit of a function, you need to substitute the value that $x$ is approaching into the function and see what value the function approaches. If the function approaches a single value, that is the limit. If the function approaches different values from the left and right sides, the limit does not exist.
The limit is a fundamental concept in calculus that allows us to analyze the behavior of functions and understand how they change over time or approach certain values. It is used to define important concepts such as continuity, differentiability, and the derivative.
Yes, a function can have a limit at a point where it is not defined. This is because the limit only looks at the behavior of the function near that point, not necessarily at the point itself. As long as the function approaches a single value from both the left and right sides, the limit exists.
The limit can tell us whether a function is approaching a single value, approaching different values from the left and right sides, or approaching infinity or negative infinity. This information can help us determine the behavior of the function near that point and make predictions about its behavior at other points.