How to Calculate Magnetic Moment of Rotating Electrons in a Straight Line?

AI Thread Summary
The discussion focuses on calculating the magnetic moment of two electrons rotating around the z-axis with a phase difference of π. The magnetic moment is derived using the formula m=(1/2c)*∫dV [r j], leading to the expression m=(qwR^2/c). There is a debate regarding the inclusion of the constant 'c', with some participants suggesting it arises from using CGS units, while others argue it should not be present in SI units. Comparisons are made to the magnetic moment of a single electron, which simplifies to m=qwR^2 without the 'c'. The conversation emphasizes the importance of unit consistency in calculations.
Maximtopsecret
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Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
 
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Is there a way you can verify this?
i.e. have you compared this answer with the magnetic moment for just one electron, same circle and speed?
 
Oh yes, I looked up a similar problem with 1 electron. There J=q/T; therefore m=0.5qwR2
What about 1/c? Is it referred to the fact that I used CGS system of units?
 
You should certainly compare like to like.
Where does the c come from in the derivation?

You can also check:
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magmom.html
... and derive the equation for a charge q going in a circle radius R.
Note: the current I is the amount of charge passing a point on the circuit every second.
 
Simon Bridge said:
You should certainly compare like to like.
Where does the c come from in the derivation?

You can also check:
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magmom.html
... and derive the equation for a charge q going in a circle radius R.
Note: the current I is the amount of charge passing a point on the circuit every second.

Yes, I checked your link above. From their formula m=I*S it follow for 2 electrons m=qwR2 - no 1/c. This result corresponds to the result of 1 electron.
But initially I tried to apply the general formula for m=(1/2c)*∫dV [r*j]; this formula was used in class where all tasks were done using CGS units.
So, I would stick to my opinion that 1/2c comes from CGS...
 
Maximtopsecret said:

Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
Maximtopsecret said:

Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
In SE units the c in the denominator would not be there. You on cgs or ?

Nice fancy equation but you could have just said m = IA, I = current, A = area.
 
rude man said:
In SE units the c in the denominator would not be there. You on cgs or ?

Nice fancy equation but you could have just said m = IA, I = current, A = area.
Yes, I do use CGS here.
 
Maximtopsecret said:
Yes, I do use CGS here.
As real physicists do! (I'm not one of them, I'm afraid) :frown:
(I meant SI of course, not SE).
rm
 
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