Find the magnitude of the acceleration of the two masses.

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Homework Help Overview

The problem involves an Atwood machine with two masses (16.4 kg and 2.9 kg) and a pulley with a specified moment of inertia and friction torque. The objective is to compute the magnitude of the acceleration of the two masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between moment of inertia and torque, and the need to establish the tension in the string. There are considerations about how to express the applied torque in terms of acceleration and the roles of different tensions in the system.

Discussion Status

Some participants have offered guidance on formulating equations related to tension and torque, while others are exploring the implications of the friction torque on the system. There is an ongoing examination of how to incorporate the various forces and torques into the equations of motion.

Contextual Notes

Participants question the relevance of the constant friction torque and its representation in the equations. There is also a discussion about whether to consider the total mass of both weights in the calculations.

mparsons06
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Homework Statement



An Atwood machine consists of two masses (16.4 kg and a 2.9 kg) strung over a 0.43 m diameter pulley whose moment of inertia is 0.031 kg·m2. If there is a constant friction torque of 0.18 N·m at the bearing, compute the magnitude of the acceleration of the two masses.

Can someone just tell me where to start please?
 
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Not sure if there's more information than the needed in that problem, but first of all you should think for instance of the relation of the moment of inertia and torque.

[tex]\tau = I\alpha[/tex]
 
Maybe I wasn't explicit enough, but to begin with this problem you will first need to state the tension of the string (T=mg-ma). With that you will be able to find the 'applied torque' in terms of the acceleration:
[tex]\tau_a = (mg - ma)r[/tex]

And once you have this, you will be able to easily use the formula I wrote in the last post.

Note that:
[tex]\tau_a - \tau_f = \tau[/tex]

and:
[tex]\alpha = a/r[/tex].
 
Last edited:
Redsummers said:
Maybe I wasn't explicit enough, but to begin with this problem you will first need to state the tension of the string (T=mg-ma). With that you will be able to find the 'applied torque' in terms of the acceleration:
[tex]\tau_a = (mg - ma)r[/tex]


Is m the total mass of both masses?
 
mparsons06 said:
Is m the total mass of both masses?

Oh you're right! then you have to think also as there are two tensions, let me develop the corresponding equations: (T1, being from the heavier mass, m1)

[tex](T_1 - T_2)r - \tau_f = I\alpha[/tex]

and according to Newton's concerning the tensions:

[tex]m_1g - T_1 = m_1a[/tex]

[tex]m_2g - T_2 = m_2a[/tex]

Thus,

[tex](T_1 - T_2)r = I\alpha + \tau_f[/tex]

[tex](T_1 - T_2) = \frac{Ia}{r} + \tau_f[/tex]

[tex]T_1 - T_2 = \frac{Ia}{r} + \tau_f[/tex]

And now you would have to plug the tension equations stated above, and do the maths to get the acceleration.
 
Where does the part about "constant friction torque of 0.18 N·m at the bearing" come into play?
 
oh the constant friction torque is simply represented as
[tex]\tau_f[/tex]
It is, as the name represents the friction done by the pulley to the string.
 

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