Find the Minimum Initial Acceleration for a Jumbo Jet Takeoff | Homework Help

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To determine the minimum initial acceleration for a jumbo jet to take off, it must reach a final velocity of 360 km/h (100 m/s) over a runway length of 1.8 km (1800 m). The relevant equation is V1^2 = V0^2 + 2a(x-x0), where the initial velocity (V0) is 0. Consistent units are crucial, requiring conversion of all measurements to meters and seconds for accurate calculations. The correct application of the formula leads to finding the necessary acceleration. Understanding unit conversion is essential for solving such physics problems effectively.
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Homework Statement



In order for a jumbo jet to take off, it must reach a final velocity of 360 km/h. Given that it moves at a constant acceleration and that the runway is 1.8 km long, find the minimum initial acceleration required to reach the final velocity. The jet starts at rest.

Homework Equations


V1^2 = V0^2 + 2a(x-x0)


The Attempt at a Solution



I tried putting the given values into this equation and nothing sensible happened. The acceleration is constant, so it should be the same at any point. Also, the jet starts at rest, so the velocity at time 0 is 0.

I don't know what's going on, please help

thanks
 
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Everything is to be done in the x coordinate.

360km/h = 100m/s = V(final), distance = 1800m

Given that, and the formula "V1^2 = V0^2 + 2a(x-x0) ", you should be able to find acceleration.

Which should be: 10000 = 0 + 3600a
 
I put the same thing in terms of kilometers and meters, what's the difference?

thanks
 
The units have to be consistent, acceleration = m/(s^2), so when plugging into the formula, length has to be in meters, and time has to be in seconds.
 
ah right. thanks.. I was suspicious of that..

this might sound stupid, but what's the easiest way to convert something into something else?

thanks
 
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