Find the points of discontinuity: f(x) = x + 1 , for x < 1 and 1/x for x ≥ 1?

jennaskim
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Find the points of discontinuity: f(x) = x + 1 , for x < 1 and 1/x for x ≥ 1?

^ supposed to be a piece-wise function.

State whether f is left- or right-continuous at each point of discontinuity.




I'm having difficulty figuring this out... please help?
 
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jennaskim said:
Find the points of discontinuity: f(x) = x + 1 , for x < 1 and 1/x for x ≥ 1?

^ supposed to be a piece-wise function.

State whether f is left- or right-continuous at each point of discontinuity.




I'm having difficulty figuring this out... please help?

Show you work so far.

RGV
 
Well i tried graphing it...but I STILL DON'T UNDERSTAND
 
jennaskim said:
Well i tried graphing it...but I STILL DON'T UNDERSTAND

Please explain exactly what you do not understand. We cannot guess about what is bothering you.

RGV
 
jennaskim said:
Well i tried graphing it...but I STILL DON'T UNDERSTAND

jennaskim, either draw your graph, or describe it

as Ray says, we need to see how far you've got, and what is confusing you
 
You can start by considering these two limits :

lim_{x→1^-} f(x)

and

lim_{x→1^+} f(x)

What happens here?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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