Find the power emitted (quantium mech)

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SUMMARY

The discussion focuses on calculating the power emitted by a blackbody at a temperature of 7000 K through a small wavelength range of 4000 to 4001 angstroms. The power emitted is derived from the formula P(λ) dλ = A(2πhc²/λ⁵) dλ. While one participant suggests using integration over the specified wavelength range, the solution provided simplifies the calculation by substituting λ = 4000 and using dλ = 10⁻¹⁰, as the variation in the expression is minimal over such a small interval.

PREREQUISITES
  • Understanding of blackbody radiation and Planck's law
  • Familiarity with the concepts of wavelength and angstroms
  • Basic knowledge of calculus, specifically integration
  • Proficiency in using physical constants such as h (Planck's constant) and c (speed of light)
NEXT STEPS
  • Review the derivation of Planck's law for blackbody radiation
  • Learn about the significance of the Stefan-Boltzmann law in thermal radiation
  • Explore numerical integration techniques for more complex power calculations
  • Investigate the impact of temperature on blackbody radiation spectra
USEFUL FOR

Students studying thermodynamics, physicists interested in quantum mechanics, and anyone involved in thermal radiation calculations.

leonne
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Homework Statement


consider a blackbody at t=7000 what is the power emitted through a hole 1m between\lambda= 4000 and 4001 angstrom


Homework Equations



P(\lambda) d\lambda=A(2\pihc2/\lambda5(...)d\lambda

The Attempt at a Solution


my question is the math, I thought u had to make a integral on both sides and have it go from 4000 to 4001, but the solution does not do this. they just plug in 4000 for \lambda and for d\lambda they have 10-10 Is both ways correct? I don't remember what i got when i did the integral
thanks
 
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Strictly speaking, your way is "more correct". They use the fact that the range for lambda is very small and the expression is not going to change a lot. This way, the integration turns into a multiplication.
 
ok thanks
 

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