- #1
Taryn
- 63
- 0
hey just wondering if someone could help me with these 2 questions!
Suppose for a function f, that 1<= f'(x)<=3 show that
4<=f(6)-f(2)<=12
I don't even no where to start... I was thinkin that in some way you could use the mean value theorem!
f(c)= [f(6)-f(2)]/4
But I wouldn't have a clue where to go from there
2. Find the primitives of the functions
secxtanx
so I sed that u=secx and that du=secxtanx
So does this mean that the answer will just be equal to one?
The last one is just hard in the fact that I am unsure of wat u should be equal to...
integral x^6lnx(dx)
Suppose for a function f, that 1<= f'(x)<=3 show that
4<=f(6)-f(2)<=12
I don't even no where to start... I was thinkin that in some way you could use the mean value theorem!
f(c)= [f(6)-f(2)]/4
But I wouldn't have a clue where to go from there
2. Find the primitives of the functions
secxtanx
so I sed that u=secx and that du=secxtanx
So does this mean that the answer will just be equal to one?
The last one is just hard in the fact that I am unsure of wat u should be equal to...
integral x^6lnx(dx)