Find the radius of convergence

JulioMarcos
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Homework Statement
Find the radius of convergence of the Series:
\sum_{i=1}^{\infty}\frac{(2n)!x^n}{(n!)^2}

The attempt at a solution
I used the Ratio Test but I always get L = |\frac{2x}{n+1}|

The answer is 1/4. I think I am mistaking with factorial.
 
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Solved. The problem was tha
(2(n+1))! = (2n + 2)(2n + 1)(2n)!
and I was doing (2(n+1))! = (2n + 2)(2n)!
because i thought you should distribute the 2
 
Ah it is always good to find your own mistake. Off the bat that was my guess... Sadly I got in the thread too late.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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