Calculating the Radius of a Circle for Masses Attached by a Cord

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To find the radius of the circle for the 2 kg mass moving at 3.5 m/s while the 4 kg mass remains at rest, the relevant equations involve tension and gravitational forces. The tension in the cord must balance the gravitational force acting on the hanging mass, while also providing the necessary centripetal force for the mass on the table. The user is unsure if their equations are set up correctly and is considering the use of orbital length in their calculations. Clarification on the correct application of these equations is needed to solve for the radius. Properly applying the equations will yield the radius required for the system to maintain equilibrium.
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Homework Statement



A block of mass m1=2kg is attached to a cord. The cord goes down through a hole in the table and is attached to mass m2=4 kg hanging below the table. The 2 kg mass moves on the table in a circle at a speed of 3.5 m/s the table top is friction less and there is no friction between the cord and the side of the hole. What is the radius of the circle if the 4 kg mass remains at rest?

Homework Equations



Sum of force x direction m1: T=mv^2/r

Sum of forces y direction m1: N-mg=mv^2/r

Sum of forces x direction m2: Mg-t= Mv^2/r

The Attempt at a Solution



I have tried to use this equations and i cannot come up wit the solution. Do i have my equation correctly in this problem?
 
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I guess you use orbital length to get the answer :P
 
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