Find the ration of the centripetal accelaration

Click For Summary

Homework Help Overview

The discussion revolves around calculating the ratio of centripetal acceleration for a helicopter blade rotating in a horizontal circle. The original poster presents a scenario involving a blade length of 6.7m and seeks to compare the centripetal acceleration at the tip of the blade to that at a point 3.0m from the center.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for centripetal acceleration and the relationship between radius, speed, and period. There are attempts to clarify how to express speed in terms of radius and period, alongside questions about the definitions of revolution and period.

Discussion Status

The conversation is ongoing, with participants exploring various interpretations of the problem. Some guidance has been offered regarding the concepts of revolution and period, but there remains a lack of clarity on how to apply these concepts to find the required centripetal acceleration.

Contextual Notes

There are indications of communication difficulties among participants, with some expressing confusion over fundamental concepts related to circular motion. The original poster has not provided complete information on their attempts, leading to further questions about their understanding of the problem.

jandominic145
Messages
30
Reaction score
0
The large blade of a helicopter is rotating in a horizontal circle. The length of the blade is 6.7m, measured from its tip to the center of the circle. find the ration of the centripetal accelaration at the end of the blade to that which exists at a point located 3.0m from the center of the circle?

the answer is 2.2

i don't know to get 2.2
 
Last edited:
Physics news on Phys.org
Show us what you have attempted so far. Start with the formula for centripetal acceleration.
 
Cyosis said:
Show us what you have attempted so far. Start with the formula for centripetal acceleration.

centripetal acceleration
Ac = V^2/r
 
Yes and you know that the blade describes a circle. So how can you calculate v in terms of the radius and period?
 
Cyosis said:
Yes and you know that the blade describes a circle. So how can you calculate v in terms of the radius and period?

Ac = 6.7m^2/3m
= 44.89m/3m
= 14.96

the answer is 2.2 not 14.96
 
The length of the blade is 6.7m, how can that be equal to its speed? Length and speed are not the same! I will ask again how can you express v in terms of the radius and period?
 
Cyosis said:
The length of the blade is 6.7m, how can that be equal to its speed? Length and speed are not the same! I will ask again how can you express v in terms of the radius and period?

i didn't understand it
 
What part do you not understand and why are you ignoring my question for the second time? If you are unwilling to cooperate we're not going to get anywhere. I will guide you to the answer, but only if you cooperate.
 
Cyosis said:
What part do you not understand and why are you ignoring my question for the second time? If you are unwilling to cooperate we're not going to get anywhere. I will guide you to the answer, but only if you cooperate.

60 degrees
 
  • #10
'the circle of degrees is 60' makes no sense to me. It is also irrelevant to the problem. For the third time now I will ask you the following question:

How can you express the speed v, in terms of the radius r, and the time it takes for one revolution T?
 
  • #11
Cyosis said:
'the circle of degrees is 60' makes no sense to me. It is also irrelevant to the problem. For the third time now I will ask you the following question:

How can you express the speed v, in terms of the radius r, and the time it takes for one revolution T?

what is T revolution
 
  • #12
As I said, the time it takes for one revolution, the period.
 
  • #13
Cyosis said:
As I said, the time it takes for one revolution, the period.

how?
 
  • #14
Could you be a little bit more specific when it comes to asking questions and giving answers. Single phrase 'sentences' really don't work well to convey a message. I do not see how the sentence you quoted from me can generate the question 'how'? How what?
 
  • #15
Cyosis said:
Could you be a little bit more specific when it comes to asking questions and giving answers. Single phrase 'sentences' really don't work well to convey a message. I do not see how the sentence you quoted from me can generate the question 'how'? How what?

the time it takes for one revolution, the period.
 
  • #16
We are having serious communication issues here. Do you know what a revolution is, do you know what a period is? If you do, explain both concepts to me.
 
  • #17
Cyosis said:
We are having serious communication issues here. Do you know what a revolution is, do you know what a period is? If you do, explain both concepts to me.

i don't know what is revolution and period
 
  • #18
The blade describes a circle, it rotates. After some time T the blade returns to its original position at that point in time it has done one full rotation called a revolution. The time it takes for the blade to make one circle is called the period. You want to know the speed of the blade at a distance r from the center.
 
  • #19
Cyosis said:
The blade describes a circle, it rotates. After some time T the blade returns to its original position at that point in time it has done one full rotation called a revolution. The time it takes for the blade to make one circle is called the period. You want to know the speed of the blade at a distance r from the center.

R is 3 m
 
  • #20
R can be all values in between 6.7 and 0. You have a formula for the centripetal acceleration with two variables r and v. r is known but v is not therefore we want to find v. I have been telling you to do this for the fourth time now.

If you pick a certain point on the propeller blade and let the blade rotate until it comes back to its original position. How much distance has that point traveled? hint: the blade describes a circle
 
  • #21
Cyosis said:
R can be all values in between 6.7 and 0. You have a formula for the centripetal acceleration with two variables r and v. r is known but v is not therefore we want to find v. I have been telling you to do this for the fourth time now.

If you pick a certain point on the propeller blade and let the blade rotate until it comes back to its original position. How much distance has that point traveled? hint: the blade describes a circle

6.7m
 
  • #22
Great another one phrase answer without any explanation to why you think that is the answer. Are you just guessing or what? The blade is 6.7m LONG and is rotating. I placed a point a distance r from the enter on the blade, never did I say the point was on the tip of the blade.

The blade is rotating it describes a circle do you see this? (answer this question)
Therefore the point on the blade follows the circumference of that circle. How much distance does the point move during one revolution? (answer this question)
 
  • #23
Cyosis said:
Great another one phrase answer without any explanation to why you think that is the answer. Are you just guessing or what? The blade is 6.7m LONG and is rotating. I placed a point a distance r from the enter on the blade, never did I say the point was on the tip of the blade.

The blade is rotating it describes a circle do you see this? (answer this question)
Therefore the point on the blade follows the circumference of that circle. How much distance does the point move during one revolution? (answer this question)

i dunno
 
  • #24
So you don't know a single one of those questions? I must say you don't make me feel like you are actually trying to understand this. So I am going to try one more time.

Do you understand and see how the blade describes the circumference of a circle when it starts rotating?
What is the circumference of that circle?

Answer both questions separately.
 
Last edited:
  • #25
Cyosis said:
So you don't know a single of those questions? I must say you don't make me feel like you are actually trying to understand this. So I am going to try one more time.

Do you understand and see how the blade describes the circumference of a circle when it starts rotating?

the length is 6.7 m and the center of the circle is 3
 
  • #26
i need to solve now
 
  • #27
No that's wrong, besides that's not even what I asked. The center of the circle is at a distance 0, the 3m value is almost half way on the blade and the 6.7m value is at the tip of the blade. Read post #24 again and answer my questions.
 
  • #28
Cyosis said:
No that's wrong, besides that's not even what I asked. The center of the circle is at a distance 0, the 3m value is almost half way on the blade and the 6.7m value is at the tip of the blade. Read post #24 again and answer my questions.
i did not understand how the blade describes the circumference of a circle when it starts rotating?
What is the circumference of that circle?

3.1416 is pi r

c=2(3.1416)r
 
  • #29
That makes no sense. What you wrote there is 3.1416=\pi r. Presumably this is the answer to the question what the circumference of the circle is? Well obviously this answer is wrong. Try again, what is the formula of the circumference of any circle?
 
  • #30
Cyosis said:
That makes no sense. What you wrote there is 3.1416=\pi r. Presumably this is the answer to the question what the circumference of the circle is? Well obviously this answer is wrong. Try again, what is the formula of the circumference of any circle?

c = 2 pi r
 

Similar threads

Replies
16
Views
973
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
7
Views
4K
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 20 ·
Replies
20
Views
5K