transgalactic
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find the solution of this ln equation:
ax=lnx
i tried:
<br /> e^{(ax)}=x<br />
<br /> e^{(ax)}-x=0<br />
what to do next??
i thought of building a taylor series around 0 for ln
but ln(0) is undefined
??
ax=lnx
i tried:
<br /> e^{(ax)}=x<br />
<br /> e^{(ax)}-x=0<br />
what to do next??
i thought of building a taylor series around 0 for ln
but ln(0) is undefined
??
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