Find the solution of this ln equation

  • Thread starter Thread starter transgalactic
  • Start date Start date
  • Tags Tags
    Ln
transgalactic
Messages
1,386
Reaction score
0
find the solution of this ln equation:
ax=lnx

i tried:
<br /> e^{(ax)}=x<br />
<br /> e^{(ax)}-x=0<br />

what to do next??
i thought of building a taylor series around 0 for ln
but ln(0) is undefined

??
 
Last edited:
Physics news on Phys.org
I'm not entirely sure, but I think such equations must be solved with a numerical method, such as Newton-Rhapson.
 
When there is any solution there are two I think.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top